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132068912795849 is a prime number
BaseRepresentation
bin11110000001110110110000…
…101000100001000011001001
3122022121122221121102212220002
4132001312300220201003021
5114302304113133431344
61144515342043212345
736550443530256011
oct3601666050410311
9568548847385802
10132068912795849
1139099125275557
121298ba0b8170b5
135890077c43523
1424882530d6c41
1510406374cc44e
hex781db0a210c9

132068912795849 has 2 divisors, whose sum is σ = 132068912795850. Its totient is φ = 132068912795848.

The previous prime is 132068912795843. The next prime is 132068912795917. The reversal of 132068912795849 is 948597219860231.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 101544558532624 + 30524354263225 = 10076932^2 + 5524885^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-132068912795849 is a prime.

It is not a weakly prime, because it can be changed into another prime (132068912795843) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66034456397924 + 66034456397925.

It is an arithmetic number, because the mean of its divisors is an integer number (66034456397925).

It is a 1-persistent number, because it is pandigital, but 2⋅132068912795849 = 264137825591698 is not.

Almost surely, 2132068912795849 is an apocalyptic number.

It is an amenable number.

132068912795849 is a deficient number, since it is larger than the sum of its proper divisors (1).

132068912795849 is an equidigital number, since it uses as much as digits as its factorization.

132068912795849 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 470292480, while the sum is 74.

The spelling of 132068912795849 in words is "one hundred thirty-two trillion, sixty-eight billion, nine hundred twelve million, seven hundred ninety-five thousand, eight hundred forty-nine".