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1320730804553 is a prime number
BaseRepresentation
bin10011001110000001101…
…100001100000101001001
311200021001000000102212012
4103032001230030011021
5133114324041221203
62450422500425305
7164263640415656
oct23160154140511
94607030012765
101320730804553
1146a134120516
12193b720a8235
13977100086b4
1447cd0946c2d
152454ddeabd8
hex13381b0c149

1320730804553 has 2 divisors, whose sum is σ = 1320730804554. Its totient is φ = 1320730804552.

The previous prime is 1320730804543. The next prime is 1320730804567. The reversal of 1320730804553 is 3554080370231.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1108718443849 + 212012360704 = 1052957^2 + 460448^2 .

It is an emirp because it is prime and its reverse (3554080370231) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1320730804553 - 28 = 1320730804297 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 1320730804553.

It is not a weakly prime, because it can be changed into another prime (1320730804543) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 660365402276 + 660365402277.

It is an arithmetic number, because the mean of its divisors is an integer number (660365402277).

Almost surely, 21320730804553 is an apocalyptic number.

It is an amenable number.

1320730804553 is a deficient number, since it is larger than the sum of its proper divisors (1).

1320730804553 is an equidigital number, since it uses as much as digits as its factorization.

1320730804553 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 302400, while the sum is 41.

The spelling of 1320730804553 in words is "one trillion, three hundred twenty billion, seven hundred thirty million, eight hundred four thousand, five hundred fifty-three".