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132075403169 is a prime number
BaseRepresentation
bin111101100000001001…
…1101011011110100001
3110121220120011122112212
41323000103223132201
54130442300400134
6140401414131505
712353644255313
oct1730023533641
9417816148485
10132075403169
1151016138266
122171b950b95
13c5bab5cb48
14656cd917b3
15368016cbce
hex1ec04eb7a1

132075403169 has 2 divisors, whose sum is σ = 132075403170. Its totient is φ = 132075403168.

The previous prime is 132075403151. The next prime is 132075403189. The reversal of 132075403169 is 961304570231.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 120834102544 + 11241300625 = 347612^2 + 106025^2 .

It is a cyclic number.

It is not a de Polignac number, because 132075403169 - 28 = 132075402913 is a prime.

It is a super-2 number, since 2×1320754031692 (a number of 23 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (132075403189) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66037701584 + 66037701585.

It is an arithmetic number, because the mean of its divisors is an integer number (66037701585).

Almost surely, 2132075403169 is an apocalyptic number.

It is an amenable number.

132075403169 is a deficient number, since it is larger than the sum of its proper divisors (1).

132075403169 is an equidigital number, since it uses as much as digits as its factorization.

132075403169 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 136080, while the sum is 41.

The spelling of 132075403169 in words is "one hundred thirty-two billion, seventy-five million, four hundred three thousand, one hundred sixty-nine".