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13207639451 is a prime number
BaseRepresentation
bin11000100110011110…
…01001010110011011
31021002110111121020112
430103033021112123
5204022123430301
610022325314535
7645204040316
oct142317112633
937073447215
1013207639451
115668406006
122687265a4b
131326402296
148d417997d
155247b99bb
hex3133c959b

13207639451 has 2 divisors, whose sum is σ = 13207639452. Its totient is φ = 13207639450.

The previous prime is 13207639429. The next prime is 13207639457. The reversal of 13207639451 is 15493670231.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 13207639451 - 218 = 13207377307 is a prime.

It is a super-2 number, since 2×132076394512 (a number of 21 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 13207639399 and 13207639408.

It is not a weakly prime, because it can be changed into another prime (13207639457) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6603819725 + 6603819726.

It is an arithmetic number, because the mean of its divisors is an integer number (6603819726).

Almost surely, 213207639451 is an apocalyptic number.

13207639451 is a deficient number, since it is larger than the sum of its proper divisors (1).

13207639451 is an equidigital number, since it uses as much as digits as its factorization.

13207639451 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 136080, while the sum is 41.

The spelling of 13207639451 in words is "thirteen billion, two hundred seven million, six hundred thirty-nine thousand, four hundred fifty-one".