Base | Representation |
---|---|
bin | 1100000000110010010110… |
… | …0110110011011001000001 |
3 | 1201202122021012201000011212 |
4 | 3000030211212303121001 |
5 | 3212343234233123121 |
6 | 44031302455415505 |
7 | 2532136004152346 |
oct | 300144546633101 |
9 | 51678235630155 |
10 | 13207655364161 |
11 | 4232376148335 |
12 | 1593895084595 |
13 | 74a626cc1c6b |
14 | 33937aadc7cd |
15 | 17d864c2c25b |
hex | c03259b3641 |
13207655364161 has 2 divisors, whose sum is σ = 13207655364162. Its totient is φ = 13207655364160.
The previous prime is 13207655364157. The next prime is 13207655364229. The reversal of 13207655364161 is 16146355670231.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 13205636209936 + 2019154225 = 3633956^2 + 44935^2 .
It is a cyclic number.
It is not a de Polignac number, because 13207655364161 - 22 = 13207655364157 is a prime.
It is not a weakly prime, because it can be changed into another prime (13207655364961) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6603827682080 + 6603827682081.
It is an arithmetic number, because the mean of its divisors is an integer number (6603827682081).
Almost surely, 213207655364161 is an apocalyptic number.
It is an amenable number.
13207655364161 is a deficient number, since it is larger than the sum of its proper divisors (1).
13207655364161 is an equidigital number, since it uses as much as digits as its factorization.
13207655364161 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2721600, while the sum is 50.
The spelling of 13207655364161 in words is "thirteen trillion, two hundred seven billion, six hundred fifty-five million, three hundred sixty-four thousand, one hundred sixty-one".
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