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13208904576113 is a prime number
BaseRepresentation
bin1100000000110111000000…
…0100001010110001110001
31201202202111021022112211012
43000031300010022301301
53212403314032413423
644032030442400305
72532211653243611
oct300156004126161
951682437275735
1013208904576113
114232957306804
121593b83500095
1374a795a56c2c
1433945899ca41
1517d8d9739078
hexc037010ac71

13208904576113 has 2 divisors, whose sum is σ = 13208904576114. Its totient is φ = 13208904576112.

The previous prime is 13208904575959. The next prime is 13208904576143. The reversal of 13208904576113 is 31167540980231.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 7350215032384 + 5858689543729 = 2711128^2 + 2420473^2 .

It is a cyclic number.

It is not a de Polignac number, because 13208904576113 - 234 = 13191724706929 is a prime.

It is a Sophie Germain prime.

It is a Curzon number.

It is not a weakly prime, because it can be changed into another prime (13208904576143) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6604452288056 + 6604452288057.

It is an arithmetic number, because the mean of its divisors is an integer number (6604452288057).

It is a 1-persistent number, because it is pandigital, but 2⋅13208904576113 = 26417809152226 is not.

Almost surely, 213208904576113 is an apocalyptic number.

It is an amenable number.

13208904576113 is a deficient number, since it is larger than the sum of its proper divisors (1).

13208904576113 is an equidigital number, since it uses as much as digits as its factorization.

13208904576113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1088640, while the sum is 50.

The spelling of 13208904576113 in words is "thirteen trillion, two hundred eight billion, nine hundred four million, five hundred seventy-six thousand, one hundred thirteen".