Base | Representation |
---|---|
bin | 11110000010001001110101… |
… | …001011010101001111000001 |
3 | 122022200121210201011001000221 |
4 | 132002021311023111033001 |
5 | 114303123032333013032 |
6 | 1144533010023343041 |
7 | 36552100136561032 |
oct | 3602116513251701 |
9 | 568617721131027 |
10 | 132089390126017 |
11 | 390a6883187815 |
12 | 129939855b1a81 |
13 | 5891c8c49683c |
14 | 2489236952a89 |
15 | 1040e350d4597 |
hex | 7822752d53c1 |
132089390126017 has 2 divisors, whose sum is σ = 132089390126018. Its totient is φ = 132089390126016.
The previous prime is 132089390125997. The next prime is 132089390126063. The reversal of 132089390126017 is 710621093980231.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 74730336698241 + 57359053427776 = 8644671^2 + 7573576^2 .
It is a cyclic number.
It is not a de Polignac number, because 132089390126017 - 211 = 132089390123969 is a prime.
It is not a weakly prime, because it can be changed into another prime (132089390166017) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66044695063008 + 66044695063009.
It is an arithmetic number, because the mean of its divisors is an integer number (66044695063009).
Almost surely, 2132089390126017 is an apocalyptic number.
It is an amenable number.
132089390126017 is a deficient number, since it is larger than the sum of its proper divisors (1).
132089390126017 is an equidigital number, since it uses as much as digits as its factorization.
132089390126017 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 979776, while the sum is 52.
The spelling of 132089390126017 in words is "one hundred thirty-two trillion, eighty-nine billion, three hundred ninety million, one hundred twenty-six thousand, seventeen".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.071 sec. • engine limits •