Base | Representation |
---|---|
bin | 1100000000111011000101… |
… | …0110111000100000000011 |
3 | 1201202212022121112220022022 |
4 | 3000032301112320200003 |
5 | 3212413040000013102 |
6 | 44032331253232055 |
7 | 2532251054223344 |
oct | 300166126704003 |
9 | 51685277486268 |
10 | 13210000001027 |
11 | 4233369686755 |
12 | 159422a33262b |
13 | 74a90b99535b |
14 | 33952026a0cb |
15 | 17d9509b95a2 |
hex | c03b15b8803 |
13210000001027 has 2 divisors, whose sum is σ = 13210000001028. Its totient is φ = 13210000001026.
The previous prime is 13210000001017. The next prime is 13210000001039. The reversal of 13210000001027 is 72010000001231.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 13210000001027 - 210 = 13210000000003 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 13210000000996 and 13210000001014.
It is not a weakly prime, because it can be changed into another prime (13210000001017) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6605000000513 + 6605000000514.
It is an arithmetic number, because the mean of its divisors is an integer number (6605000000514).
Almost surely, 213210000001027 is an apocalyptic number.
13210000001027 is a deficient number, since it is larger than the sum of its proper divisors (1).
13210000001027 is an equidigital number, since it uses as much as digits as its factorization.
13210000001027 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 84, while the sum is 17.
Adding to 13210000001027 its reverse (72010000001231), we get a palindrome (85220000002258).
The spelling of 13210000001027 in words is "thirteen trillion, two hundred ten billion, one thousand, twenty-seven".
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