Base | Representation |
---|---|
bin | 11000100110110000… |
… | …01100101010010011 |
3 | 1021002121222011012002 |
4 | 30103120030222103 |
5 | 204023230343212 |
6 | 10022452224215 |
7 | 645233152262 |
oct | 142330145223 |
9 | 37077864162 |
10 | 13210012307 |
11 | 5669786848 |
12 | 268800b06b |
13 | 1326a5333b |
14 | 8d45d65d9 |
15 | 524ad7ac2 |
hex | 31360ca93 |
13210012307 has 2 divisors, whose sum is σ = 13210012308. Its totient is φ = 13210012306.
The previous prime is 13210012259. The next prime is 13210012337. The reversal of 13210012307 is 70321001231.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13210012307 is a prime.
It is not a weakly prime, because it can be changed into another prime (13210012337) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6605006153 + 6605006154.
It is an arithmetic number, because the mean of its divisors is an integer number (6605006154).
Almost surely, 213210012307 is an apocalyptic number.
13210012307 is a deficient number, since it is larger than the sum of its proper divisors (1).
13210012307 is an equidigital number, since it uses as much as digits as its factorization.
13210012307 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 252, while the sum is 20.
Adding to 13210012307 its reverse (70321001231), we get a palindrome (83531013538).
The spelling of 13210012307 in words is "thirteen billion, two hundred ten million, twelve thousand, three hundred seven".
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