Base | Representation |
---|---|
bin | 11110000010010011111011… |
… | …011110011010100011010011 |
3 | 122022201122210101022210001111 |
4 | 132002103323132122203103 |
5 | 114303312234200210232 |
6 | 1144542002004314151 |
7 | 36552632632351003 |
oct | 3602237336324323 |
9 | 568648711283044 |
10 | 132100233210067 |
11 | 3910043788a301 |
12 | 12995ab09a2957 |
13 | 5892cc9a403c5 |
14 | 2489984a58003 |
15 | 104136beca047 |
hex | 7824fb79a8d3 |
132100233210067 has 2 divisors, whose sum is σ = 132100233210068. Its totient is φ = 132100233210066.
The previous prime is 132100233210053. The next prime is 132100233210133. The reversal of 132100233210067 is 760012332001231.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-132100233210067 is a prime.
It is a super-2 number, since 2×1321002332100672 (a number of 29 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (132100233210017) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66050116605033 + 66050116605034.
It is an arithmetic number, because the mean of its divisors is an integer number (66050116605034).
Almost surely, 2132100233210067 is an apocalyptic number.
132100233210067 is a deficient number, since it is larger than the sum of its proper divisors (1).
132100233210067 is an equidigital number, since it uses as much as digits as its factorization.
132100233210067 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 9072, while the sum is 31.
Adding to 132100233210067 its reverse (760012332001231), we get a palindrome (892112565211298).
The spelling of 132100233210067 in words is "one hundred thirty-two trillion, one hundred billion, two hundred thirty-three million, two hundred ten thousand, sixty-seven".
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