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132100411323 = 3531376064381
BaseRepresentation
bin111101100000111001…
…1000100111110111011
3110121222022020012021210
41323001303010332323
54131020201130243
6140404110134203
712354366653346
oct1730163047673
9417868205253
10132100411323
1151029269261
12217281b1363
13c5c30a797a
14657242145d
15368245c933
hex1ec1cc4fbb

132100411323 has 16 divisors (see below), whose sum is σ = 180767098656. Its totient is φ = 85774590720.

The previous prime is 132100411307. The next prime is 132100411337. The reversal of 132100411323 is 323114001231.

It is not a de Polignac number, because 132100411323 - 24 = 132100411307 is a prime.

It is a super-2 number, since 2×1321004113232 (a number of 23 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 132100411323.

It is not an unprimeable number, because it can be changed into a prime (132100411423) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 3010408 + ... + 3053973.

It is an arithmetic number, because the mean of its divisors is an integer number (11297943666).

Almost surely, 2132100411323 is an apocalyptic number.

132100411323 is a deficient number, since it is larger than the sum of its proper divisors (48666687333).

132100411323 is a wasteful number, since it uses less digits than its factorization.

132100411323 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 6064574.

The product of its (nonzero) digits is 432, while the sum is 21.

Adding to 132100411323 its reverse (323114001231), we get a palindrome (455214412554).

The spelling of 132100411323 in words is "one hundred thirty-two billion, one hundred million, four hundred eleven thousand, three hundred twenty-three".

Divisors: 1 3 53 137 159 411 7261 21783 6064381 18193143 321412193 830820197 964236579 2492460591 44033470441 132100411323