Base | Representation |
---|---|
bin | 111101100000111001… |
… | …1000101000000011111 |
3 | 110121222022020012102111 |
4 | 1323001303011000133 |
5 | 4131020201131143 |
6 | 140404110134451 |
7 | 12354366653551 |
oct | 1730163050037 |
9 | 417868205374 |
10 | 132100411423 |
11 | 51029269342 |
12 | 217281b1427 |
13 | c5c30a7a26 |
14 | 65724214d1 |
15 | 368245c99d |
hex | 1ec1cc501f |
132100411423 has 2 divisors, whose sum is σ = 132100411424. Its totient is φ = 132100411422.
The previous prime is 132100411409. The next prime is 132100411441. The reversal of 132100411423 is 324114001231.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 132100411423 - 213 = 132100403231 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 132100411394 and 132100411403.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (132140411423) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66050205711 + 66050205712.
It is an arithmetic number, because the mean of its divisors is an integer number (66050205712).
Almost surely, 2132100411423 is an apocalyptic number.
132100411423 is a deficient number, since it is larger than the sum of its proper divisors (1).
132100411423 is an equidigital number, since it uses as much as digits as its factorization.
132100411423 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 576, while the sum is 22.
Adding to 132100411423 its reverse (324114001231), we get a palindrome (456214412654).
The spelling of 132100411423 in words is "one hundred thirty-two billion, one hundred million, four hundred eleven thousand, four hundred twenty-three".
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