Base | Representation |
---|---|
bin | 11110000010010100101001… |
… | …110011010100010010111000 |
3 | 122022201201210112211020000011 |
4 | 132002110221303110102320 |
5 | 114303320332133111100 |
6 | 1144542211051151304 |
7 | 36552661120614400 |
oct | 3602245163242270 |
9 | 568651715736004 |
10 | 132101010441400 |
11 | 391007a6589750 |
12 | 12996089145534 |
13 | 58930c1a808c0 |
14 | 2489a19d77800 |
15 | 10413b5355bba |
hex | 782529cd44b8 |
132101010441400 has 576 divisors, whose sum is σ = 434214685044000. Its totient is φ = 36696483532800.
The previous prime is 132101010441397. The next prime is 132101010441481. The reversal of 132101010441400 is 4144010101231.
132101010441400 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is a Harshad number since it is a multiple of its sum of digits (22).
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 143 ways as a sum of consecutive naturals, for example, 39015366 + ... + 42265834.
Almost surely, 2132101010441400 is an apocalyptic number.
132101010441400 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 132101010441400, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (217107342522000).
132101010441400 is an abundant number, since it is smaller than the sum of its proper divisors (302113674602600).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
132101010441400 is a wasteful number, since it uses less digits than its factorization.
132101010441400 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 3250552 (or 3250536 counting only the distinct ones).
The product of its (nonzero) digits is 384, while the sum is 22.
Adding to 132101010441400 its reverse (4144010101231), we get a palindrome (136245020542631).
The spelling of 132101010441400 in words is "one hundred thirty-two trillion, one hundred one billion, ten million, four hundred forty-one thousand, four hundred".
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