Base | Representation |
---|---|
bin | 11110000010010100110110… |
… | …011010010110011100100110 |
3 | 122022201202100021220112102111 |
4 | 132002110312122112130212 |
5 | 114303321300313003142 |
6 | 1144542244045431234 |
7 | 36552666300053503 |
oct | 3602246632263446 |
9 | 568652307815374 |
10 | 132101222000422 |
11 | 391008a4a47114 |
12 | 12996127b6b51a |
13 | 589312685425c |
14 | 2489a3a0c84aa |
15 | 10413c8be4e17 |
hex | 782536696726 |
132101222000422 has 4 divisors (see below), whose sum is σ = 198151833000636. Its totient is φ = 66050611000210.
The previous prime is 132101222000413. The next prime is 132101222000437. The reversal of 132101222000422 is 224000222101231.
It is a semiprime because it is the product of two primes.
It is a junction number, because it is equal to n+sod(n) for n = 132101222000393 and 132101222000402.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 33025305500104 + ... + 33025305500107.
It is an arithmetic number, because the mean of its divisors is an integer number (49537958250159).
Almost surely, 2132101222000422 is an apocalyptic number.
132101222000422 is a deficient number, since it is larger than the sum of its proper divisors (66050611000214).
132101222000422 is an equidigital number, since it uses as much as digits as its factorization.
132101222000422 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 66050611000213.
The product of its (nonzero) digits is 768, while the sum is 22.
Adding to 132101222000422 its reverse (224000222101231), we get a palindrome (356101444101653).
The spelling of 132101222000422 in words is "one hundred thirty-two trillion, one hundred one billion, two hundred twenty-two million, four hundred twenty-two", and thus it is an aban number.
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