Base | Representation |
---|---|
bin | 10011001110010011000… |
… | …011001000110011111011 |
3 | 11200021210022000101101102 |
4 | 103032103003020303323 |
5 | 133120423120030042 |
6 | 2450511422442015 |
7 | 164304105003635 |
oct | 23162303106373 |
9 | 4607708011342 |
10 | 1321022033147 |
11 | 46a273553903 |
12 | 19403373330b |
13 | 97758454bcb |
14 | 47d1b4b5a55 |
15 | 24569775b32 |
hex | 133930c8cfb |
1321022033147 has 2 divisors, whose sum is σ = 1321022033148. Its totient is φ = 1321022033146.
The previous prime is 1321022033099. The next prime is 1321022033153. The reversal of 1321022033147 is 7413302201231.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1321022033147 - 210 = 1321022032123 is a prime.
It is not a weakly prime, because it can be changed into another prime (1321022033197) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 660511016573 + 660511016574.
It is an arithmetic number, because the mean of its divisors is an integer number (660511016574).
Almost surely, 21321022033147 is an apocalyptic number.
1321022033147 is a deficient number, since it is larger than the sum of its proper divisors (1).
1321022033147 is an equidigital number, since it uses as much as digits as its factorization.
1321022033147 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 6048, while the sum is 29.
Adding to 1321022033147 its reverse (7413302201231), we get a palindrome (8734324234378).
The spelling of 1321022033147 in words is "one trillion, three hundred twenty-one billion, twenty-two million, thirty-three thousand, one hundred forty-seven".
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