Base | Representation |
---|---|
bin | 11000100110110010… |
… | …01100100101011001 |
3 | 1021002122110110100111 |
4 | 30103121030211121 |
5 | 204023312233022 |
6 | 10022502004321 |
7 | 645235322524 |
oct | 142331144531 |
9 | 37078413314 |
10 | 13210274137 |
11 | 5669945535 |
12 | 26881166a1 |
13 | 1326b15578 |
14 | 8d4663bbb |
15 | 524b3a477 |
hex | 31364c959 |
13210274137 has 2 divisors, whose sum is σ = 13210274138. Its totient is φ = 13210274136.
The previous prime is 13210274117. The next prime is 13210274141. The reversal of 13210274137 is 73147201231.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 8277178441 + 4933095696 = 90979^2 + 70236^2 .
It is a cyclic number.
It is not a de Polignac number, because 13210274137 - 219 = 13209749849 is a prime.
It is a super-2 number, since 2×132102741372 (a number of 21 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 13210274099 and 13210274108.
It is not a weakly prime, because it can be changed into another prime (13210274117) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6605137068 + 6605137069.
It is an arithmetic number, because the mean of its divisors is an integer number (6605137069).
Almost surely, 213210274137 is an apocalyptic number.
It is an amenable number.
13210274137 is a deficient number, since it is larger than the sum of its proper divisors (1).
13210274137 is an equidigital number, since it uses as much as digits as its factorization.
13210274137 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 7056, while the sum is 31.
Adding to 13210274137 its reverse (73147201231), we get a palindrome (86357475368).
The spelling of 13210274137 in words is "thirteen billion, two hundred ten million, two hundred seventy-four thousand, one hundred thirty-seven".
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