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13210302041 is a prime number
BaseRepresentation
bin11000100110110010…
…10011011001011001
31021002122111212121222
430103121103121121
5204023314131131
610022502341425
7645235500056
oct142331233131
937078455558
1013210302041
1156699644a2
12268812a875
131326b25191
148d467002d
15524b4387b
hex313653659

13210302041 has 2 divisors, whose sum is σ = 13210302042. Its totient is φ = 13210302040.

The previous prime is 13210302037. The next prime is 13210302059. The reversal of 13210302041 is 14020301231.

13210302041 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 13201090816 + 9211225 = 114896^2 + 3035^2 .

It is a cyclic number.

It is not a de Polignac number, because 13210302041 - 22 = 13210302037 is a prime.

It is not a weakly prime, because it can be changed into another prime (13210352041) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6605151020 + 6605151021.

It is an arithmetic number, because the mean of its divisors is an integer number (6605151021).

Almost surely, 213210302041 is an apocalyptic number.

It is an amenable number.

13210302041 is a deficient number, since it is larger than the sum of its proper divisors (1).

13210302041 is an equidigital number, since it uses as much as digits as its factorization.

13210302041 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 144, while the sum is 17.

Adding to 13210302041 its reverse (14020301231), we get a palindrome (27230603272).

The spelling of 13210302041 in words is "thirteen billion, two hundred ten million, three hundred two thousand, forty-one".