Base | Representation |
---|---|
bin | 11110000010010110100111… |
… | …000000010100001111011011 |
3 | 122022201221012221101201010202 |
4 | 132002112213000110033123 |
5 | 114303334132404013201 |
6 | 1144543155325332415 |
7 | 36553064145232121 |
oct | 3602264700241733 |
9 | 568657187351122 |
10 | 132103111001051 |
11 | 3910168426a263 |
12 | 1299657470710b |
13 | 58933680063c8 |
14 | 2489b78d2b911 |
15 | 104148997dc6b |
hex | 7825a70143db |
132103111001051 has 2 divisors, whose sum is σ = 132103111001052. Its totient is φ = 132103111001050.
The previous prime is 132103111001047. The next prime is 132103111001123. The reversal of 132103111001051 is 150100111301231.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 132103111001051 - 22 = 132103111001047 is a prime.
It is not a weakly prime, because it can be changed into another prime (132103111001551) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66051555500525 + 66051555500526.
It is an arithmetic number, because the mean of its divisors is an integer number (66051555500526).
Almost surely, 2132103111001051 is an apocalyptic number.
132103111001051 is a deficient number, since it is larger than the sum of its proper divisors (1).
132103111001051 is an equidigital number, since it uses as much as digits as its factorization.
132103111001051 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 90, while the sum is 20.
Adding to 132103111001051 its reverse (150100111301231), we get a palindrome (282203222302282).
The spelling of 132103111001051 in words is "one hundred thirty-two trillion, one hundred three billion, one hundred eleven million, one thousand, fifty-one".
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