Base | Representation |
---|---|
bin | 111101100001001011… |
… | …1101101100101010011 |
3 | 110121222222022002210020 |
4 | 1323002113231211103 |
5 | 4131030130433203 |
6 | 140405052034523 |
7 | 12354544412004 |
oct | 1730227554523 |
9 | 417888262706 |
10 | 132110014803 |
11 | 51033728518 |
12 | 2172b462a43 |
13 | c5c508abc0 |
14 | 65738011ab |
15 | 3683208153 |
hex | 1ec25ed953 |
132110014803 has 32 divisors (see below), whose sum is σ = 194385838080. Its totient is φ = 79290005760.
The previous prime is 132110014789. The next prime is 132110014819. The reversal of 132110014803 is 308410011231.
It is not a de Polignac number, because 132110014803 - 218 = 132109752659 is a prime.
It is a super-2 number, since 2×1321100148032 (a number of 23 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (132110014843) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 5717688 + ... + 5740746.
It is an arithmetic number, because the mean of its divisors is an integer number (6074557440).
Almost surely, 2132110014803 is an apocalyptic number.
132110014803 is a gapful number since it is divisible by the number (13) formed by its first and last digit.
132110014803 is a deficient number, since it is larger than the sum of its proper divisors (62275823277).
132110014803 is a wasteful number, since it uses less digits than its factorization.
132110014803 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 26699.
The product of its (nonzero) digits is 576, while the sum is 24.
The spelling of 132110014803 in words is "one hundred thirty-two billion, one hundred ten million, fourteen thousand, eight hundred three".
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