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132110113 is a prime number
BaseRepresentation
bin1111101111111…
…01011100100001
3100012120220000011
413313331130201
5232310010423
621035324521
73162626452
oct767753441
9305526004
10132110113
1168633313
12382b0741
13214a7085
141378d129
15b8e8b0d
hex7dfd721

132110113 has 2 divisors, whose sum is σ = 132110114. Its totient is φ = 132110112.

The previous prime is 132110093. The next prime is 132110123. The reversal of 132110113 is 311011231.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 113039424 + 19070689 = 10632^2 + 4367^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-132110113 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 132110093 and 132110102.

It is not a weakly prime, because it can be changed into another prime (132110123) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66055056 + 66055057.

It is an arithmetic number, because the mean of its divisors is an integer number (66055057).

Almost surely, 2132110113 is an apocalyptic number.

It is an amenable number.

132110113 is a deficient number, since it is larger than the sum of its proper divisors (1).

132110113 is an equidigital number, since it uses as much as digits as its factorization.

132110113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 18, while the sum is 13.

The square root of 132110113 is about 11493.9163473552. The cubic root of 132110113 is about 509.3058774459.

Adding to 132110113 its reverse (311011231), we get a palindrome (443121344).

The spelling of 132110113 in words is "one hundred thirty-two million, one hundred ten thousand, one hundred thirteen".