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132110114000203 is a prime number
BaseRepresentation
bin11110000010011101001000…
…011010101000110101001011
3122022202121021222202220222201
4132002131020122220311023
5114303443003141001303
61144550314252101031
736553432531602223
oct3602351032506513
9568677258686881
10132110114000203
1139104648282169
12129979a9a64777
135893c12b1c4a1
14248a241029083
15104174968b81d
hex7827486a8d4b

132110114000203 has 2 divisors, whose sum is σ = 132110114000204. Its totient is φ = 132110114000202.

The previous prime is 132110114000107. The next prime is 132110114000239. The reversal of 132110114000203 is 302000411011231.

It is a strong prime.

It is an emirp because it is prime and its reverse (302000411011231) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 132110114000203 - 29 = 132110113999691 is a prime.

It is a super-2 number, since 2×1321101140002032 (a number of 29 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (132110114000303) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66055057000101 + 66055057000102.

It is an arithmetic number, because the mean of its divisors is an integer number (66055057000102).

Almost surely, 2132110114000203 is an apocalyptic number.

132110114000203 is a deficient number, since it is larger than the sum of its proper divisors (1).

132110114000203 is an equidigital number, since it uses as much as digits as its factorization.

132110114000203 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 144, while the sum is 19.

Adding to 132110114000203 its reverse (302000411011231), we get a palindrome (434110525011434).

The spelling of 132110114000203 in words is "one hundred thirty-two trillion, one hundred ten billion, one hundred fourteen million, two hundred three", and thus it is an aban number.