Base | Representation |
---|---|
bin | 11110000010011101001000… |
… | …011010101000110101001011 |
3 | 122022202121021222202220222201 |
4 | 132002131020122220311023 |
5 | 114303443003141001303 |
6 | 1144550314252101031 |
7 | 36553432531602223 |
oct | 3602351032506513 |
9 | 568677258686881 |
10 | 132110114000203 |
11 | 39104648282169 |
12 | 129979a9a64777 |
13 | 5893c12b1c4a1 |
14 | 248a241029083 |
15 | 104174968b81d |
hex | 7827486a8d4b |
132110114000203 has 2 divisors, whose sum is σ = 132110114000204. Its totient is φ = 132110114000202.
The previous prime is 132110114000107. The next prime is 132110114000239. The reversal of 132110114000203 is 302000411011231.
It is a strong prime.
It is an emirp because it is prime and its reverse (302000411011231) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 132110114000203 - 29 = 132110113999691 is a prime.
It is a super-2 number, since 2×1321101140002032 (a number of 29 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (132110114000303) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66055057000101 + 66055057000102.
It is an arithmetic number, because the mean of its divisors is an integer number (66055057000102).
Almost surely, 2132110114000203 is an apocalyptic number.
132110114000203 is a deficient number, since it is larger than the sum of its proper divisors (1).
132110114000203 is an equidigital number, since it uses as much as digits as its factorization.
132110114000203 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 144, while the sum is 19.
Adding to 132110114000203 its reverse (302000411011231), we get a palindrome (434110525011434).
The spelling of 132110114000203 in words is "one hundred thirty-two trillion, one hundred ten billion, one hundred fourteen million, two hundred three", and thus it is an aban number.
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