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13211024220307 is a prime number
BaseRepresentation
bin1100000000111110111001…
…1001111110000010010011
31201202221221222210122000201
43000033232121332002103
53212422134200022212
644033021042000031
72532315332025364
oct300175631760223
951687858718021
1013211024220307
114233844841871
121594475346017
1374aa42c32274
143395ba2bdb6b
1517d9b0881b57
hexc03ee67e093

13211024220307 has 2 divisors, whose sum is σ = 13211024220308. Its totient is φ = 13211024220306.

The previous prime is 13211024220299. The next prime is 13211024220319. The reversal of 13211024220307 is 70302242011231.

13211024220307 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It is an emirp because it is prime and its reverse (70302242011231) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 13211024220307 - 23 = 13211024220299 is a prime.

It is not a weakly prime, because it can be changed into another prime (13211024220337) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6605512110153 + 6605512110154.

It is an arithmetic number, because the mean of its divisors is an integer number (6605512110154).

Almost surely, 213211024220307 is an apocalyptic number.

13211024220307 is a deficient number, since it is larger than the sum of its proper divisors (1).

13211024220307 is an equidigital number, since it uses as much as digits as its factorization.

13211024220307 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 4032, while the sum is 28.

Adding to 13211024220307 its reverse (70302242011231), we get a palindrome (83513266231538).

The spelling of 13211024220307 in words is "thirteen trillion, two hundred eleven billion, twenty-four million, two hundred twenty thousand, three hundred seven".