Base | Representation |
---|---|
bin | 11110000010011101011011… |
… | …011001010001101000011011 |
3 | 122022202122010011220211022022 |
4 | 132002131123121101220123 |
5 | 114303444131144111024 |
6 | 1144550410024445055 |
7 | 36553443446206121 |
oct | 3602353331215033 |
9 | 568678104824268 |
10 | 132110432410139 |
11 | 391047a0a90277 |
12 | 12997a7861978b |
13 | 5893c63a94a31 |
14 | 248a271431911 |
15 | 10417675d535e |
hex | 78275b651a1b |
132110432410139 has 2 divisors, whose sum is σ = 132110432410140. Its totient is φ = 132110432410138.
The previous prime is 132110432410123. The next prime is 132110432410207. The reversal of 132110432410139 is 931014234011231.
It is a weak prime.
It is an emirp because it is prime and its reverse (931014234011231) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 132110432410139 - 24 = 132110432410123 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 132110432410099 and 132110432410108.
It is not a weakly prime, because it can be changed into another prime (132110432410739) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66055216205069 + 66055216205070.
It is an arithmetic number, because the mean of its divisors is an integer number (66055216205070).
Almost surely, 2132110432410139 is an apocalyptic number.
132110432410139 is a deficient number, since it is larger than the sum of its proper divisors (1).
132110432410139 is an equidigital number, since it uses as much as digits as its factorization.
132110432410139 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 15552, while the sum is 35.
The spelling of 132110432410139 in words is "one hundred thirty-two trillion, one hundred ten billion, four hundred thirty-two million, four hundred ten thousand, one hundred thirty-nine".
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