Base | Representation |
---|---|
bin | 10011001110011000100… |
… | …010000011100001000001 |
3 | 11200022000201010000010002 |
4 | 103032120202003201001 |
5 | 133121120142232001 |
6 | 2450524510245345 |
7 | 164306302630562 |
oct | 23163042034101 |
9 | 4608021100102 |
10 | 1321114024001 |
11 | 46a310474a02 |
12 | 19405a4b6855 |
13 | 97771523075 |
14 | 47d297c0169 |
15 | 2457289746b |
hex | 13398883841 |
1321114024001 has 2 divisors, whose sum is σ = 1321114024002. Its totient is φ = 1321114024000.
The previous prime is 1321114023997. The next prime is 1321114024019. The reversal of 1321114024001 is 1004204111231.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1252331093776 + 68782930225 = 1119076^2 + 262265^2 .
It is a cyclic number.
It is not a de Polignac number, because 1321114024001 - 22 = 1321114023997 is a prime.
It is a super-2 number, since 2×13211140240012 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1321114024201) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 660557012000 + 660557012001.
It is an arithmetic number, because the mean of its divisors is an integer number (660557012001).
Almost surely, 21321114024001 is an apocalyptic number.
It is an amenable number.
1321114024001 is a deficient number, since it is larger than the sum of its proper divisors (1).
1321114024001 is an equidigital number, since it uses as much as digits as its factorization.
1321114024001 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 192, while the sum is 20.
Adding to 1321114024001 its reverse (1004204111231), we get a palindrome (2325318135232).
The spelling of 1321114024001 in words is "one trillion, three hundred twenty-one billion, one hundred fourteen million, twenty-four thousand, one".
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