Base | Representation |
---|---|
bin | 11000100110111001… |
… | …00000001110110001 |
3 | 1021002201002111112001 |
4 | 30103130200032301 |
5 | 204024023003131 |
6 | 10022532334001 |
7 | 645245563120 |
oct | 142334401661 |
9 | 37081074461 |
10 | 13211141041 |
11 | 566a38788a |
12 | 2688474301 |
13 | 132705a027 |
14 | 8d480bab7 |
15 | 524c5c261 |
hex | 3137203b1 |
13211141041 has 4 divisors (see below), whose sum is σ = 15098446912. Its totient is φ = 11323835172.
The previous prime is 13211141017. The next prime is 13211141057. The reversal of 13211141041 is 14014111231.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 13211141041 - 217 = 13211009969 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (13211141341) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 943652925 + ... + 943652938.
It is an arithmetic number, because the mean of its divisors is an integer number (3774611728).
Almost surely, 213211141041 is an apocalyptic number.
It is an amenable number.
13211141041 is a deficient number, since it is larger than the sum of its proper divisors (1887305871).
13211141041 is an equidigital number, since it uses as much as digits as its factorization.
13211141041 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1887305870.
The product of its (nonzero) digits is 96, while the sum is 19.
Adding to 13211141041 its reverse (14014111231), we get a palindrome (27225252272).
The spelling of 13211141041 in words is "thirteen billion, two hundred eleven million, one hundred forty-one thousand, forty-one".
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