Base | Representation |
---|---|
bin | 11000100110111001… |
… | …00000001111000001 |
3 | 1021002201002111112122 |
4 | 30103130200033001 |
5 | 204024023003212 |
6 | 10022532334025 |
7 | 645245563142 |
oct | 142334401701 |
9 | 37081074478 |
10 | 13211141057 |
11 | 566a3878a4 |
12 | 2688474315 |
13 | 132705a03a |
14 | 8d480bac9 |
15 | 524c5c272 |
hex | 3137203c1 |
13211141057 has 2 divisors, whose sum is σ = 13211141058. Its totient is φ = 13211141056.
The previous prime is 13211141017. The next prime is 13211141059. The reversal of 13211141057 is 75014111231.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 13167792001 + 43349056 = 114751^2 + 6584^2 .
It is a cyclic number.
It is not a de Polignac number, because 13211141057 - 28 = 13211140801 is a prime.
Together with 13211141059, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (13211141059) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6605570528 + 6605570529.
It is an arithmetic number, because the mean of its divisors is an integer number (6605570529).
Almost surely, 213211141057 is an apocalyptic number.
It is an amenable number.
13211141057 is a deficient number, since it is larger than the sum of its proper divisors (1).
13211141057 is an equidigital number, since it uses as much as digits as its factorization.
13211141057 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 840, while the sum is 26.
Adding to 13211141057 its reverse (75014111231), we get a palindrome (88225252288).
The spelling of 13211141057 in words is "thirteen billion, two hundred eleven million, one hundred forty-one thousand, fifty-seven".
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