Base | Representation |
---|---|
bin | 1100000000111111101000… |
… | …1010101110111101101011 |
3 | 1201202222110202010011121002 |
4 | 3000033322022232331223 |
5 | 3212423040204144003 |
6 | 44033052411305215 |
7 | 2532323246233355 |
oct | 300177212567553 |
9 | 51688422104532 |
10 | 13211221553003 |
11 | 4233936172841 |
12 | 159450b44b20b |
13 | 74aa74a94486 |
14 | 3395d85aa0d5 |
15 | 17d9c2d60a88 |
hex | c03fa2aef6b |
13211221553003 has 2 divisors, whose sum is σ = 13211221553004. Its totient is φ = 13211221553002.
The previous prime is 13211221552999. The next prime is 13211221553083. The reversal of 13211221553003 is 30035512211231.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 13211221553003 - 22 = 13211221552999 is a prime.
It is not a weakly prime, because it can be changed into another prime (13211221553083) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6605610776501 + 6605610776502.
It is an arithmetic number, because the mean of its divisors is an integer number (6605610776502).
Almost surely, 213211221553003 is an apocalyptic number.
13211221553003 is a deficient number, since it is larger than the sum of its proper divisors (1).
13211221553003 is an equidigital number, since it uses as much as digits as its factorization.
13211221553003 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 5400, while the sum is 29.
Adding to 13211221553003 its reverse (30035512211231), we get a palindrome (43246733764234).
The spelling of 13211221553003 in words is "thirteen trillion, two hundred eleven billion, two hundred twenty-one million, five hundred fifty-three thousand, three".
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