Base | Representation |
---|---|
bin | 11110000010100000000000… |
… | …100100010001101011010111 |
3 | 122022202220021022021112100210 |
4 | 132002200000210101223113 |
5 | 114304020320101101201 |
6 | 1144551545015340503 |
7 | 36553602225321051 |
oct | 3602400044215327 |
9 | 568686238245323 |
10 | 132113203534551 |
11 | 39105993236038 |
12 | 12998510681733 |
13 | 58942b5c21a15 |
14 | 248a45549a8d1 |
15 | 104187aa191d6 |
hex | 782800911ad7 |
132113203534551 has 16 divisors (see below), whose sum is σ = 177225915976704. Its totient is φ = 87538100188704.
The previous prime is 132113203534531. The next prime is 132113203534553. The reversal of 132113203534551 is 155435302311231.
It is a happy number.
It is a de Polignac number, because none of the positive numbers 2k-132113203534551 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (132113203534553) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 10611616 + ... + 19412181.
It is an arithmetic number, because the mean of its divisors is an integer number (11076619748544).
Almost surely, 2132113203534551 is an apocalyptic number.
132113203534551 is a deficient number, since it is larger than the sum of its proper divisors (45112712442153).
132113203534551 is a wasteful number, since it uses less digits than its factorization.
132113203534551 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 30032750.
The product of its (nonzero) digits is 162000, while the sum is 39.
Adding to 132113203534551 its reverse (155435302311231), we get a palindrome (287548505845782).
The spelling of 132113203534551 in words is "one hundred thirty-two trillion, one hundred thirteen billion, two hundred three million, five hundred thirty-four thousand, five hundred fifty-one".
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