Base | Representation |
---|---|
bin | 11000100110111010… |
… | …01100001101000001 |
3 | 1021002201102122120212 |
4 | 30103131030031001 |
5 | 204024044234103 |
6 | 10022540243505 |
7 | 645250243202 |
oct | 142335141501 |
9 | 37081378525 |
10 | 13211321153 |
11 | 566a4a0138 |
12 | 2688540595 |
13 | 13270c0cc4 |
14 | 8d48575a9 |
15 | 524c957d8 |
hex | 31374c341 |
13211321153 has 2 divisors, whose sum is σ = 13211321154. Its totient is φ = 13211321152.
The previous prime is 13211321131. The next prime is 13211321159. The reversal of 13211321153 is 35112311231.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 12712111504 + 499209649 = 112748^2 + 22343^2 .
It is a cyclic number.
It is not a de Polignac number, because 13211321153 - 230 = 12137579329 is a prime.
It is a Sophie Germain prime.
It is a Curzon number.
It is not a weakly prime, because it can be changed into another prime (13211321159) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6605660576 + 6605660577.
It is an arithmetic number, because the mean of its divisors is an integer number (6605660577).
Almost surely, 213211321153 is an apocalyptic number.
It is an amenable number.
13211321153 is a deficient number, since it is larger than the sum of its proper divisors (1).
13211321153 is an equidigital number, since it uses as much as digits as its factorization.
13211321153 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 540, while the sum is 23.
Adding to 13211321153 its reverse (35112311231), we get a palindrome (48323632384).
The spelling of 13211321153 in words is "thirteen billion, two hundred eleven million, three hundred twenty-one thousand, one hundred fifty-three".
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