Base | Representation |
---|---|
bin | 10011001110011001101… |
… | …111111100001101111001 |
3 | 11200022002010112022102201 |
4 | 103032121233330031321 |
5 | 133121140404110322 |
6 | 2450530520030201 |
7 | 164306641315414 |
oct | 23163157741571 |
9 | 4608063468381 |
10 | 1321134441337 |
11 | 46a320a4a837 |
12 | 194065302361 |
13 | 97775821429 |
14 | 47d2c3b6b7b |
15 | 2457457bd27 |
hex | 13399bfc379 |
1321134441337 has 2 divisors, whose sum is σ = 1321134441338. Its totient is φ = 1321134441336.
The previous prime is 1321134441311. The next prime is 1321134441349. The reversal of 1321134441337 is 7331444311231.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 769881650041 + 551252791296 = 877429^2 + 742464^2 .
It is a cyclic number.
It is not a de Polignac number, because 1321134441337 - 215 = 1321134408569 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1321134441296 and 1321134441305.
It is not a weakly prime, because it can be changed into another prime (1321134441307) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 660567220668 + 660567220669.
It is an arithmetic number, because the mean of its divisors is an integer number (660567220669).
Almost surely, 21321134441337 is an apocalyptic number.
It is an amenable number.
1321134441337 is a deficient number, since it is larger than the sum of its proper divisors (1).
1321134441337 is an equidigital number, since it uses as much as digits as its factorization.
1321134441337 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 72576, while the sum is 37.
Adding to 1321134441337 its reverse (7331444311231), we get a palindrome (8652578752568).
The spelling of 1321134441337 in words is "one trillion, three hundred twenty-one billion, one hundred thirty-four million, four hundred forty-one thousand, three hundred thirty-seven".
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