Base | Representation |
---|---|
bin | 11110000010100000110000… |
… | …101001110101111110101011 |
3 | 122022202222100112100110221212 |
4 | 132002200300221311332223 |
5 | 114304023443114102311 |
6 | 1144552201035223335 |
7 | 36553631222603633 |
oct | 3602406051657653 |
9 | 568688315313855 |
10 | 132114010300331 |
11 | 39106267678114 |
12 | 129986b68a7b4b |
13 | 58943b4103317 |
14 | 248a4d06a76c3 |
15 | 10418c677ac8b |
hex | 782830a75fab |
132114010300331 has 2 divisors, whose sum is σ = 132114010300332. Its totient is φ = 132114010300330.
The previous prime is 132114010300309. The next prime is 132114010300339. The reversal of 132114010300331 is 133003010411231.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 132114010300331 - 26 = 132114010300267 is a prime.
It is a super-2 number, since 2×1321140103003312 (a number of 29 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 132114010300297 and 132114010300306.
It is not a weakly prime, because it can be changed into another prime (132114010300339) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66057005150165 + 66057005150166.
It is an arithmetic number, because the mean of its divisors is an integer number (66057005150166).
Almost surely, 2132114010300331 is an apocalyptic number.
132114010300331 is a deficient number, since it is larger than the sum of its proper divisors (1).
132114010300331 is an equidigital number, since it uses as much as digits as its factorization.
132114010300331 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 648, while the sum is 23.
Adding to 132114010300331 its reverse (133003010411231), we get a palindrome (265117020711562).
The spelling of 132114010300331 in words is "one hundred thirty-two trillion, one hundred fourteen billion, ten million, three hundred thousand, three hundred thirty-one".
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