Base | Representation |
---|---|
bin | 111101100001010110… |
… | …1011010100111111001 |
3 | 110122000101000011022211 |
4 | 1323002231122213321 |
5 | 4131033110014223 |
6 | 140405414015121 |
7 | 12354643646335 |
oct | 1730255324771 |
9 | 418011004284 |
10 | 132115704313 |
11 | 5103696409a |
12 | 217313474a1 |
13 | c5c6300788 |
14 | 65744827c5 |
15 | 368397dd0d |
hex | 1ec2b5a9f9 |
132115704313 has 2 divisors, whose sum is σ = 132115704314. Its totient is φ = 132115704312.
The previous prime is 132115704247. The next prime is 132115704319. The reversal of 132115704313 is 313407511231.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 74636600809 + 57479103504 = 273197^2 + 239748^2 .
It is a cyclic number.
It is not a de Polignac number, because 132115704313 - 213 = 132115696121 is a prime.
It is a super-2 number, since 2×1321157043132 (a number of 23 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (132115704319) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66057852156 + 66057852157.
It is an arithmetic number, because the mean of its divisors is an integer number (66057852157).
Almost surely, 2132115704313 is an apocalyptic number.
It is an amenable number.
132115704313 is a deficient number, since it is larger than the sum of its proper divisors (1).
132115704313 is an equidigital number, since it uses as much as digits as its factorization.
132115704313 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 7560, while the sum is 31.
The spelling of 132115704313 in words is "one hundred thirty-two billion, one hundred fifteen million, seven hundred four thousand, three hundred thirteen".
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