Base | Representation |
---|---|
bin | 111101100001010111… |
… | …1010100111101011111 |
3 | 110122000101221121200212 |
4 | 1323002233110331133 |
5 | 4131033222033112 |
6 | 140405432443035 |
7 | 12354651134264 |
oct | 1730257247537 |
9 | 418011847625 |
10 | 132116205407 |
11 | 5103717661a |
12 | 2173154947b |
13 | c5c6447894 |
14 | 657457326b |
15 | 3683a2c522 |
hex | 1ec2bd4f5f |
132116205407 has 4 divisors (see below), whose sum is σ = 132311355576. Its totient is φ = 131921055240.
The previous prime is 132116205391. The next prime is 132116205433. The reversal of 132116205407 is 704502611231.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 132116205407 - 24 = 132116205391 is a prime.
It is a super-2 number, since 2×1321162054072 (a number of 23 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (132116205437) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 97574069 + ... + 97575422.
It is an arithmetic number, because the mean of its divisors is an integer number (33077838894).
Almost surely, 2132116205407 is an apocalyptic number.
132116205407 is a deficient number, since it is larger than the sum of its proper divisors (195150169).
132116205407 is an equidigital number, since it uses as much as digits as its factorization.
132116205407 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 195150168.
The product of its (nonzero) digits is 10080, while the sum is 32.
Adding to 132116205407 its reverse (704502611231), we get a palindrome (836618816638).
The spelling of 132116205407 in words is "one hundred thirty-two billion, one hundred sixteen million, two hundred five thousand, four hundred seven".
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