Base | Representation |
---|---|
bin | 1100000001000001100011… |
… | …0001100010000000000000 |
3 | 1201210000210112100000100000 |
4 | 3000100120301202000000 |
5 | 3212430113132240000 |
6 | 44033215353200000 |
7 | 2532342052632120 |
oct | 300203061420000 |
9 | 51700715300300 |
10 | 13211735040000 |
11 | 423407a001162 |
12 | 1594633400000 |
13 | 74ab2728c333 |
14 | 339646872c80 |
15 | 17da02e90000 |
hex | c0418c62000 |
13211735040000 has 3360 divisors, whose sum is σ = 59465999488896. Its totient is φ = 2866544640000.
The previous prime is 13211735039983. The next prime is 13211735040001. The reversal of 13211735040000 is 4053711231.
13211735040000 is a `hidden beast` number, since 13 + 211 + 7 + 35 + 0 + 400 + 0 + 0 = 666.
It is a tau number, because it is divible by the number of its divisors (3360).
It is a Harshad number since it is a multiple of its sum of digits (27).
It is not an unprimeable number, because it can be changed into a prime (13211735040001) by changing a digit.
It is a polite number, since it can be written in 239 ways as a sum of consecutive naturals, for example, 322237439980 + ... + 322237440020.
Almost surely, 213211735040000 is an apocalyptic number.
13211735040000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 13211735040000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (29732999744448).
13211735040000 is an abundant number, since it is smaller than the sum of its proper divisors (46254264448896).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13211735040000 is an frugal number, since it uses more digits than its factorization.
13211735040000 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 146 (or 95 counting only the distinct ones).
The product of its (nonzero) digits is 2520, while the sum is 27.
Adding to 13211735040000 its reverse (4053711231), we get a palindrome (13215788751231).
The spelling of 13211735040000 in words is "thirteen trillion, two hundred eleven billion, seven hundred thirty-five million, forty thousand".
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