Base | Representation |
---|---|
bin | 111101100001011110… |
… | …1111001000100011011 |
3 | 110122000200010120220011 |
4 | 1323002331321010123 |
5 | 4131040211221243 |
6 | 140410050342351 |
7 | 12355025445241 |
oct | 1730275710433 |
9 | 418020116804 |
10 | 132120023323 |
11 | 51039344022 |
12 | 2173288a9b7 |
13 | c5c71835c2 |
14 | 6574c88791 |
15 | 368403389d |
hex | 1ec2f7911b |
132120023323 has 2 divisors, whose sum is σ = 132120023324. Its totient is φ = 132120023322.
The previous prime is 132120023279. The next prime is 132120023351. The reversal of 132120023323 is 323320021231.
It is a strong prime.
It is an emirp because it is prime and its reverse (323320021231) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 132120023323 - 217 = 132119892251 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 132120023294 and 132120023303.
It is not a weakly prime, because it can be changed into another prime (132120023383) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66060011661 + 66060011662.
It is an arithmetic number, because the mean of its divisors is an integer number (66060011662).
Almost surely, 2132120023323 is an apocalyptic number.
132120023323 is a deficient number, since it is larger than the sum of its proper divisors (1).
132120023323 is an equidigital number, since it uses as much as digits as its factorization.
132120023323 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1296, while the sum is 22.
Adding to 132120023323 its reverse (323320021231), we get a palindrome (455440044554).
The spelling of 132120023323 in words is "one hundred thirty-two billion, one hundred twenty million, twenty-three thousand, three hundred twenty-three".
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