13212022332433 has 2 divisors, whose sum is σ = 13212022332434. Its totient is φ = 13212022332432.

The previous prime is 13212022332427. The next prime is 13212022332461. The reversal of 13212022332433 is 33423322021231.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 11672110103809 + 1539912228624 = 3416447^2 + 1240932^2 .

It is an emirp because it is prime and its reverse (33423322021231) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 13212022332433 - 2²⁹ = 13211485461521 is a prime.

It is a super-4 number, since 4×13212022332433⁴ (a number of 54 digits) contains 4444 as substring. Note that it is a super-d number also for d = 2.

It is a junction number, because it is equal to n+sod(n) for n = 13212022332395 and 13212022332404.

It is not a weakly prime, because it can be changed into another prime (13212022330433) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6606011166216 + 6606011166217.

It is an arithmetic number, because the mean of its divisors is an integer number (6606011166217).

Almost surely, 2^{13212022332433} is an apocalyptic number.

It is an amenable number.

13212022332433 is a deficient number, since it is larger than the sum of its proper divisors (1).

13212022332433 is an equidigital number, since it uses as much as digits as its factorization.

13212022332433 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 31104, while the sum is 31.

Adding to 13212022332433 its reverse (33423322021231), we get a palindrome (46635344353664).

The spelling of 13212022332433 in words is "thirteen trillion, two hundred twelve billion, twenty-two million, three hundred thirty-two thousand, four hundred thirty-three".