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132121023286849 is a prime number
BaseRepresentation
bin11110000010100111010010…
…101010010000111001000001
3122022210122110021112002220021
4132002213102222100321001
5114304132323430134344
61144555321000013441
736554300060161522
oct3602472252207101
9568718407462807
10132121023286849
1139109236291743
1212999b33461281
135894c6100529c
14248a997c44849
151041b872acb84
hex7829d2a90e41

132121023286849 has 2 divisors, whose sum is σ = 132121023286850. Its totient is φ = 132121023286848.

The previous prime is 132121023286817. The next prime is 132121023286877. The reversal of 132121023286849 is 948682320121231.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 92270778869824 + 39850244417025 = 9605768^2 + 6312705^2 .

It is an emirp because it is prime and its reverse (948682320121231) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 132121023286849 - 25 = 132121023286817 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 132121023286796 and 132121023286805.

It is not a weakly prime, because it can be changed into another prime (132121023236849) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66060511643424 + 66060511643425.

It is an arithmetic number, because the mean of its divisors is an integer number (66060511643425).

Almost surely, 2132121023286849 is an apocalyptic number.

It is an amenable number.

132121023286849 is a deficient number, since it is larger than the sum of its proper divisors (1).

132121023286849 is an equidigital number, since it uses as much as digits as its factorization.

132121023286849 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1990656, while the sum is 52.

The spelling of 132121023286849 in words is "one hundred thirty-two trillion, one hundred twenty-one billion, twenty-three million, two hundred eighty-six thousand, eight hundred forty-nine".