13212103320 has 256 divisors, whose sum is σ = 47588083200. Its totient is φ = 3241244160.

The previous prime is 13212103319. The next prime is 13212103327. The reversal of 13212103320 is 2330121231.

13212103320 is a `hidden beast` number, since 1 + 321 + 2 + 10 + 332 + 0 = 666.

It is a Harshad number since it is a multiple of its sum of digits (18).

It is a junction number, because it is equal to n+sod(n) for n = 13212103293 and 13212103302.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13212103327) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 4645819 + ... + 4648661.

It is an arithmetic number, because the mean of its divisors is an integer number (185890950).

Almost surely, 2^13212103320 is an apocalyptic number.

13212103320 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 13212103320, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (23794041600).

13212103320 is an abundant number, since it is smaller than the sum of its proper divisors (34375979880).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13212103320 is a wasteful number, since it uses less digits than its factorization.

13212103320 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3207 (or 3197 counting only the distinct ones).

The product of its (nonzero) digits is 216, while the sum is 18.

Adding to 13212103320 its reverse (2330121231), we get a palindrome (15542224551).

The spelling of 13212103320 in words is "thirteen billion, two hundred twelve million, one hundred three thousand, three hundred twenty".