Base | Representation |
---|---|
bin | 11110000010101000011011… |
… | …011000001111111010110011 |
3 | 122022210202121022012020202011 |
4 | 132002220123120033322303 |
5 | 114304142323241113133 |
6 | 1145000042021103351 |
7 | 36554342233135312 |
oct | 3602503330177263 |
9 | 568722538166664 |
10 | 132122243301043 |
11 | 39109801a18436 |
12 | 1299a213b57b57 |
13 | 58950c69b6488 |
14 | 248aa71ca4279 |
15 | 1041c0944d6cd |
hex | 782a1b60feb3 |
132122243301043 has 2 divisors, whose sum is σ = 132122243301044. Its totient is φ = 132122243301042.
The previous prime is 132122243301029. The next prime is 132122243301089. The reversal of 132122243301043 is 340103342221231.
It is a weak prime.
It is an emirp because it is prime and its reverse (340103342221231) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 132122243301043 - 233 = 132113653366451 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 132122243300996 and 132122243301014.
It is not a weakly prime, because it can be changed into another prime (132122243301023) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66061121650521 + 66061121650522.
It is an arithmetic number, because the mean of its divisors is an integer number (66061121650522).
Almost surely, 2132122243301043 is an apocalyptic number.
132122243301043 is a deficient number, since it is larger than the sum of its proper divisors (1).
132122243301043 is an equidigital number, since it uses as much as digits as its factorization.
132122243301043 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 20736, while the sum is 31.
Adding to 132122243301043 its reverse (340103342221231), we get a palindrome (472225585522274).
The spelling of 132122243301043 in words is "one hundred thirty-two trillion, one hundred twenty-two billion, two hundred forty-three million, three hundred one thousand, forty-three".
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