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132123011310000 = 24325443286111933
BaseRepresentation
bin11110000010101001001001…
…001001111110000110110000
3122022210211120211100010222100
4132002221021021332012300
5114304200411343410000
61145000250134140400
736554400250121424
oct3602511111760660
9568724524303870
10132123011310000
113910a066498987
121299a3a91b1700
1358951b9b48049
14248ab05ca2b84
151041c51aa6a00
hex782a4927e1b0

132123011310000 has 600 divisors, whose sum is σ = 473003570918736. Its totient is φ = 34398524160000.

The previous prime is 132123011309921. The next prime is 132123011310001. The reversal of 132123011310000 is 13110321231.

132123011310000 is a `hidden beast` number, since 1 + 321 + 2 + 30 + 1 + 1 + 310 + 0 + 0 + 0 = 666.

It is a tau number, because it is divible by the number of its divisors (600).

It is a super-2 number, since 2×1321230113100002 (a number of 29 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (18).

It is not an unprimeable number, because it can be changed into a prime (132123011310001) by changing a digit.

It is a polite number, since it can be written in 119 ways as a sum of consecutive naturals, for example, 11072064034 + ... + 11072075966.

Almost surely, 2132123011310000 is an apocalyptic number.

132123011310000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 132123011310000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (236501785459368).

132123011310000 is an abundant number, since it is smaller than the sum of its proper divisors (340880559608736).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

132123011310000 is a wasteful number, since it uses less digits than its factorization.

132123011310000 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 14871 (or 14847 counting only the distinct ones).

The product of its (nonzero) digits is 108, while the sum is 18.

Adding to 132123011310000 its reverse (13110321231), we get a palindrome (132136121631231).

The spelling of 132123011310000 in words is "one hundred thirty-two trillion, one hundred twenty-three billion, eleven million, three hundred ten thousand".