132123200000131 has 2 divisors, whose sum is σ = 132123200000132. Its totient is φ = 132123200000130.

The previous prime is 132123200000089. The next prime is 132123200000177. The reversal of 132123200000131 is 131000002321231.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 132123200000131 - 2⁷ = 132123200000003 is a prime.

It is a super-2 number, since 2×132123200000131² (a number of 29 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 132123200000099 and 132123200000108.

It is not a weakly prime, because it can be changed into another prime (132123200000431) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66061600000065 + 66061600000066.

It is an arithmetic number, because the mean of its divisors is an integer number (66061600000066).

Almost surely, 2^{132123200000131} is an apocalyptic number.

132123200000131 is a deficient number, since it is larger than the sum of its proper divisors (1).

132123200000131 is an equidigital number, since it uses as much as digits as its factorization.

132123200000131 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 216, while the sum is 19.

Adding to 132123200000131 its reverse (131000002321231), we get a palindrome (263123202321362).

The spelling of 132123200000131 in words is "one hundred thirty-two trillion, one hundred twenty-three billion, two hundred million, one hundred thirty-one", and thus it is an aban number.