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13212412143303 = 3239105541174599
BaseRepresentation
bin1100000001000100000100…
…1000011110011011000111
31201210002112201102102110010
43000101001020132123013
53212433010002041203
644033410502001303
72532364614131202
oct300210110363307
951702481372403
1013212412143303
11423439723196a
1215947a2116233
1374ac04642989
143396ac76a939
1517da4263d303
hexc044121e6c7

13212412143303 has 16 divisors (see below), whose sum is σ = 17690527872000. Its totient is φ = 8771286709920.

The previous prime is 13212412143277. The next prime is 13212412143319. The reversal of 13212412143303 is 30334121421231.

It is not a de Polignac number, because 13212412143303 - 242 = 8814365632199 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13212412143803) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 75585598 + ... + 75760196.

It is an arithmetic number, because the mean of its divisors is an integer number (1105657992000).

Almost surely, 213212412143303 is an apocalyptic number.

13212412143303 is a deficient number, since it is larger than the sum of its proper divisors (4478115728697).

13212412143303 is a wasteful number, since it uses less digits than its factorization.

13212412143303 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 280382.

The product of its (nonzero) digits is 10368, while the sum is 30.

Adding to 13212412143303 its reverse (30334121421231), we get a palindrome (43546533564534).

The spelling of 13212412143303 in words is "thirteen trillion, two hundred twelve billion, four hundred twelve million, one hundred forty-three thousand, three hundred three".

Divisors: 1 3 239 717 105541 174599 316623 523797 25224299 41729161 75672897 125187483 18427353059 55282059177 4404137381101 13212412143303