Base | Representation |
---|---|
bin | 11110000010101010010001… |
… | …110110111000100010101010 |
3 | 122022210221201211111000102121 |
4 | 132002222101312320202222 |
5 | 114304210411121340432 |
6 | 1145001011145221454 |
7 | 36554442420515134 |
oct | 3602522166704252 |
9 | 568727654430377 |
10 | 132124231043242 |
11 | 3910a631a52589 |
12 | 1299a68979188a |
13 | 589535275b3a9 |
14 | 248abbdc8c054 |
15 | 1041cc3bde197 |
hex | 782a91db88aa |
132124231043242 has 4 divisors (see below), whose sum is σ = 198186346564866. Its totient is φ = 66062115521620.
The previous prime is 132124231043239. The next prime is 132124231043297. The reversal of 132124231043242 is 242340132421231.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 103902732906361 + 28221498136881 = 10193269^2 + 5312391^2 .
It is a junction number, because it is equal to n+sod(n) for n = 132124231043198 and 132124231043207.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 33031057760809 + ... + 33031057760812.
Almost surely, 2132124231043242 is an apocalyptic number.
132124231043242 is a deficient number, since it is larger than the sum of its proper divisors (66062115521624).
132124231043242 is an equidigital number, since it uses as much as digits as its factorization.
132124231043242 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 66062115521623.
The product of its (nonzero) digits is 55296, while the sum is 34.
Adding to 132124231043242 its reverse (242340132421231), we get a palindrome (374464363464473).
The spelling of 132124231043242 in words is "one hundred thirty-two trillion, one hundred twenty-four billion, two hundred thirty-one million, forty-three thousand, two hundred forty-two".
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