Base | Representation |
---|---|
bin | 11110000010101010010111… |
… | …111000110010000001001011 |
3 | 122022210221222212211112001022 |
4 | 132002222113320302001023 |
5 | 114304211113021012412 |
6 | 1145001025201343055 |
7 | 36554445056413565 |
oct | 3602522770620113 |
9 | 568727885745038 |
10 | 132124332204107 |
11 | 3910a684067201 |
12 | 1299a6b7637a8b |
13 | 589536a6ba3a9 |
14 | 248abcd4a2335 |
15 | 1041ccca22a72 |
hex | 782a97e3204b |
132124332204107 has 2 divisors, whose sum is σ = 132124332204108. Its totient is φ = 132124332204106.
The previous prime is 132124332204047. The next prime is 132124332204173. The reversal of 132124332204107 is 701402233421231.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 132124332204107 - 214 = 132124332187723 is a prime.
It is a super-2 number, since 2×1321243322041072 (a number of 29 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (132124332294107) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66062166102053 + 66062166102054.
It is an arithmetic number, because the mean of its divisors is an integer number (66062166102054).
Almost surely, 2132124332204107 is an apocalyptic number.
132124332204107 is a deficient number, since it is larger than the sum of its proper divisors (1).
132124332204107 is an equidigital number, since it uses as much as digits as its factorization.
132124332204107 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 48384, while the sum is 35.
Adding to 132124332204107 its reverse (701402233421231), we get a palindrome (833526565625338).
The spelling of 132124332204107 in words is "one hundred thirty-two trillion, one hundred twenty-four billion, three hundred thirty-two million, two hundred four thousand, one hundred seven".
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