Base | Representation |
---|---|
bin | 11000100111000011… |
… | …01110110001100101 |
3 | 1021002210200010012121 |
4 | 30103201232301211 |
5 | 204024400330313 |
6 | 10023021545541 |
7 | 645263331130 |
oct | 142341566145 |
9 | 37083603177 |
10 | 13212511333 |
11 | 567013335a |
12 | 2688a152b1 |
13 | 1327419958 |
14 | 8d4a87217 |
15 | 524e2d28d |
hex | 31386ec65 |
13212511333 has 16 divisors (see below), whose sum is σ = 16504003584. Its totient is φ = 10314996480.
The previous prime is 13212511321. The next prime is 13212511357. The reversal of 13212511333 is 33311521231.
13212511333 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a cyclic number.
It is not a de Polignac number, because 13212511333 - 221 = 13210414181 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 13212511298 and 13212511307.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13212511133) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1787110 + ... + 1794487.
It is an arithmetic number, because the mean of its divisors is an integer number (1031500224).
Almost surely, 213212511333 is an apocalyptic number.
It is an amenable number.
13212511333 is a deficient number, since it is larger than the sum of its proper divisors (3291492251).
13212511333 is a wasteful number, since it uses less digits than its factorization.
13212511333 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 3581652.
The product of its digits is 1620, while the sum is 25.
The spelling of 13212511333 in words is "thirteen billion, two hundred twelve million, five hundred eleven thousand, three hundred thirty-three".
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