Search a number
-
+
13212814003200 = 210335272730823
BaseRepresentation
bin1100000001000101100100…
…0101011100110000000000
31201210010120201121000121000
43000101121011130300000
53212434320341100300
644033514415132000
72532410563650330
oct300213105346000
951703521530530
1013212814003200
114234583058189
121594894814000
1374ac699859b6
14339709c970c0
1517da67a6cc00
hexc045915cc00

13212814003200 has 528 divisors, whose sum is σ = 55452767541760. Its totient is φ = 3020070666240.

The previous prime is 13212814003163. The next prime is 13212814003201. The reversal of 13212814003200 is 230041821231.

13212814003200 is a `hidden beast` number, since 1 + 3 + 21 + 281 + 40 + 0 + 320 + 0 = 666.

It is a super-2 number, since 2×132128140032002 (a number of 27 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (27).

It is not an unprimeable number, because it can be changed into a prime (13212814003201) by changing a digit.

It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 3472989 + ... + 6203811.

Almost surely, 213212814003200 is an apocalyptic number.

13212814003200 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 13212814003200, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (27726383770880).

13212814003200 is an abundant number, since it is smaller than the sum of its proper divisors (42239953538560).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13212814003200 is a wasteful number, since it uses less digits than its factorization.

13212814003200 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2730869 (or 2730840 counting only the distinct ones).

The product of its (nonzero) digits is 2304, while the sum is 27.

Adding to 13212814003200 its reverse (230041821231), we get a palindrome (13442855824431).

The spelling of 13212814003200 in words is "thirteen trillion, two hundred twelve billion, eight hundred fourteen million, three thousand, two hundred".