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132130001114414 = 266065000557207
BaseRepresentation
bin11110000010101111101001…
…110001111101010100101110
3122022211111121221220000001022
4132002233221301331110232
5114304304220241130124
61145003403510014142
736555035413355102
oct3602575161752456
9568744557800038
10132130001114414
1139112023009446
121299b81a047352
135895a61cc13a4
14248b1aa327902
151042010559c5e
hex782be9c7d52e

132130001114414 has 4 divisors (see below), whose sum is σ = 198195001671624. Its totient is φ = 66065000557206.

The previous prime is 132130001114389. The next prime is 132130001114443. The reversal of 132130001114414 is 414411100031231.

It is a semiprime because it is the product of two primes.

It is a super-3 number, since 3×1321300011144143 (a number of 43 digits) contains 333 as substring.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 33032500278602 + ... + 33032500278605.

It is an arithmetic number, because the mean of its divisors is an integer number (49548750417906).

Almost surely, 2132130001114414 is an apocalyptic number.

132130001114414 is a deficient number, since it is larger than the sum of its proper divisors (66065000557210).

132130001114414 is an equidigital number, since it uses as much as digits as its factorization.

132130001114414 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 66065000557209.

The product of its (nonzero) digits is 1152, while the sum is 26.

Adding to 132130001114414 its reverse (414411100031231), we get a palindrome (546541101145645).

The spelling of 132130001114414 in words is "one hundred thirty-two trillion, one hundred thirty billion, one million, one hundred fourteen thousand, four hundred fourteen".

Divisors: 1 2 66065000557207 132130001114414