Base | Representation |
---|---|
bin | 11110000010101111101011… |
… | …000011001111111101101011 |
3 | 122022211111200102222122220001 |
4 | 132002233223003033331223 |
5 | 114304304241220040202 |
6 | 1145003405550443431 |
7 | 36555036062451316 |
oct | 3602575303177553 |
9 | 568744612878801 |
10 | 132130022424427 |
11 | 39112034043a25 |
12 | 1299b825203577 |
13 | 5895a66542b71 |
14 | 248b1ad0b397d |
15 | 1042012368d87 |
hex | 782beb0cff6b |
132130022424427 has 2 divisors, whose sum is σ = 132130022424428. Its totient is φ = 132130022424426.
The previous prime is 132130022424331. The next prime is 132130022424443. The reversal of 132130022424427 is 724424220031231.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 132130022424427 - 215 = 132130022391659 is a prime.
It is not a weakly prime, because it can be changed into another prime (132130022421427) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66065011212213 + 66065011212214.
It is an arithmetic number, because the mean of its divisors is an integer number (66065011212214).
Almost surely, 2132130022424427 is an apocalyptic number.
132130022424427 is a deficient number, since it is larger than the sum of its proper divisors (1).
132130022424427 is an equidigital number, since it uses as much as digits as its factorization.
132130022424427 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 129024, while the sum is 37.
Adding to 132130022424427 its reverse (724424220031231), we get a palindrome (856554242455658).
The spelling of 132130022424427 in words is "one hundred thirty-two trillion, one hundred thirty billion, twenty-two million, four hundred twenty-four thousand, four hundred twenty-seven".
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