Search a number
-
+
132130023303 = 344043341101
BaseRepresentation
bin111101100001110010…
…0000010011110000111
3110122001100221122021210
41323003210002132013
54131100241221203
6140411044542503
712355206444555
oct1730344023607
9418040848253
10132130023303
1151043a54173
12217360b1a33
13c5c9275155
14657632cbd5
153684d5b803
hex1ec3902787

132130023303 has 4 divisors (see below), whose sum is σ = 176173364408. Its totient is φ = 88086682200.

The previous prime is 132130023301. The next prime is 132130023331. The reversal of 132130023303 is 303320031231.

It is a semiprime because it is the product of two primes.

It is not a de Polignac number, because 132130023303 - 21 = 132130023301 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 132130023303.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (132130023301) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 22021670548 + ... + 22021670553.

It is an arithmetic number, because the mean of its divisors is an integer number (44043341102).

Almost surely, 2132130023303 is an apocalyptic number.

132130023303 is a deficient number, since it is larger than the sum of its proper divisors (44043341105).

132130023303 is an equidigital number, since it uses as much as digits as its factorization.

132130023303 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 44043341104.

The product of its (nonzero) digits is 972, while the sum is 21.

Adding to 132130023303 its reverse (303320031231), we get a palindrome (435450054534).

The spelling of 132130023303 in words is "one hundred thirty-two billion, one hundred thirty million, twenty-three thousand, three hundred three".

Divisors: 1 3 44043341101 132130023303