Base | Representation |
---|---|
bin | 11110000010101111111100… |
… | …010000011101011001100011 |
3 | 122022211112102120011220100001 |
4 | 132002233330100131121203 |
5 | 114304310334120200003 |
6 | 1145003454342040431 |
7 | 36555046166244136 |
oct | 3602577420353143 |
9 | 568745376156301 |
10 | 132130311100003 |
11 | 39112171a93187 |
12 | 1299b8a5a19117 |
13 | 5895ab12a7308 |
14 | 248b1d957a21d |
15 | 104202c88c61d |
hex | 782bfc41d663 |
132130311100003 has 2 divisors, whose sum is σ = 132130311100004. Its totient is φ = 132130311100002.
The previous prime is 132130311099979. The next prime is 132130311100013. The reversal of 132130311100003 is 300001113031231.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 132130311100003 - 225 = 132130277545571 is a prime.
It is a super-2 number, since 2×1321303111000032 (a number of 29 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (132130311100013) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66065155550001 + 66065155550002.
It is an arithmetic number, because the mean of its divisors is an integer number (66065155550002).
Almost surely, 2132130311100003 is an apocalyptic number.
132130311100003 is a deficient number, since it is larger than the sum of its proper divisors (1).
132130311100003 is an equidigital number, since it uses as much as digits as its factorization.
132130311100003 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 162, while the sum is 19.
Adding to 132130311100003 its reverse (300001113031231), we get a palindrome (432131424131234).
The spelling of 132130311100003 in words is "one hundred thirty-two trillion, one hundred thirty billion, three hundred eleven million, one hundred thousand, three".
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